Java for LeetCode 208 Implement Trie (Prefix Tree)

Implement a trie with insert, search, and startsWith methods.

Note:
You may assume that all inputs are consist of lowercase letters a-z.

解题思路:

参考百度百科:Trie树

已经给出了详细的代码:

JAVA实现如下:

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class TrieNode {
    // Initialize your data structure here.
    int num;// 有多少单词通过这个节点,即节点字符出现的次数
    TrieNode[] son;// 所有的儿子节点
    boolean isEnd;// 是不是最后一个节点
    char val;// 节点的值
 
    TrieNode() {
        this.num = 1;
        this.son = new TrieNode[26];
        this.isEnd = false;
    }
}
 
public class Trie {
    private TrieNode root;
 
    public Trie() {
        root = new TrieNode();
    }
 
    public void insert(String word) {
        if (word == null || word.length() == 0)
            return;
        TrieNode node = this.root;
        char[] letters = word.toCharArray();
        for (int i = 0; i < word.length(); i++) {
            int pos = letters[i] - 'a';
            if (node.son[pos] == null) {
                node.son[pos] = new TrieNode();
                node.son[pos].val = letters[i];
            } else {
                node.son[pos].num++;
            }
            node = node.son[pos];
        }
        node.isEnd = true;
    }
 
    // Returns if the word is in the trie.
    public boolean search(String word) {
        if (word == null || word.length() == 0) {
            return false;
        }
        TrieNode node = root;
        char[] letters = word.toCharArray();
        for (int i = 0; i < word.length(); i++) {
            int pos = letters[i] - 'a';
            if (node.son[pos] != null) {
                node = node.son[pos];
            } else {
                return false;
            }
        }
        return node.isEnd;
    }
 
    // Returns if there is any word in the trie
    // that starts with the given prefix.
    public boolean startsWith(String prefix) {
        if (prefix == null || prefix.length() == 0) {
            return false;
        }
        TrieNode node = root;
        char[] letters = prefix.toCharArray();
        for (int i = 0; i < prefix.length(); i++) {
            int pos = letters[i] - 'a';
            if (node.son[pos] != null) {
                node = node.son[pos];
            } else {
                return false;
            }
        }
        return true;
    }
}
 
// Your Trie object will be instantiated and called as such:
// Trie trie = new Trie();
// trie.insert("somestring");
// trie.search("key");

 

posted @   TonyLuis  阅读(1473)  评论(0编辑  收藏  举报
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