http://10.16.23.21:8080/JudgeOnline/showproblem?problem_id=1897

(1)简化版的括号序列;

(2)dp顺序,长度由0起递增,以便于递推的实现。

具体代码:

View Code
#include<stdio.h>
#include<string.h>
#define N 300
char ch[N];
int dp[N][N] ;
int main()
{
    int i, j, k, t, n;
    while(scanf("%s", ch)!=EOF)
    {
        if(strcmp(ch, "end")==0) break;
        n=strlen(ch);
        memset(dp, 0, sizeof(dp));
        for(k=0;k<n;k++)
            for(i=0,j=k;j<n;i++,j++)
            {
                if(ch[i]=='('&&ch[j]==')'||ch[i]=='['&&ch[j]==']')
                    dp[i][j]>?=dp[i+1][j-1]+2;
                for(t=i;t<j;t++)
                    dp[i][j]>?=dp[i][t]+dp[t+1][j];
            }
        printf("%d\n", dp[0][n-1]);
    }
    return 0;
}