sql统计-关于学生成绩
学生成绩表(stuscore):
姓名:name |
课程:subject |
分数:score |
学号:stuid |
张三 |
数学 |
89 |
1 |
张三 |
语文 |
80 |
1 |
张三 |
英语 |
70 |
1 |
李四 |
数学 |
90 |
2 |
李四 |
语文 |
70 |
2 |
李四 |
英语 |
80 |
2 |
问题:
1. 计算每个人的总成绩并排名(要求显示字段:姓名,总成绩)
2. 计算每个人的总成绩并排名(要求显示字段: 学号,姓名,总成绩)
3. 计算每个人单科的最高成绩(要求显示字段: 学号,姓名,课程,最高成绩)
4. 计算每个人的平均成绩(要求显示字段: 学号,姓名,平均成绩)
5. 列出各门课程成绩最好的学生(要求显示字段: 学号,姓名,科目,成绩)
6. 列出各门课程成绩最好的两位学生(要求显示字段: 学号,姓名,科目,成绩)
7. 统计如下:
学号 |
姓名 |
语文 |
数学 |
英语 |
总分 |
平均分 |
|
|
|
|
|
|
|
8.列出各门课程的平均成绩(要求显示字段:课程,平均成绩)
9.列出数学成绩的排名(要求显示字段:学号,姓名,成绩,排名)
10.列出数学成绩在2-3名的学生(要求显示字段:学号,姓名,科目,成绩)
11.求出李四的数学成绩的排名
12.统计如下:
课程 |
不及格(0-59)个 |
良(60-80)个 |
优(81-100)个 |
|
|
|
|
13.统计如下:数学:张三(50分),李四(90分),王五(90分),赵六(76分)
答案:
1. 计算每个人的总成绩并排名
2. 计算每个人的总成绩并排名
(
select stuid,sum(score) as allscore from stuscore group by stuid
)t2
where t1.stuid=t2.stuid
order by t2.allscore desc
3. 计算每个人单科的最高成绩
(
select stuid,max(score) as maxscore from stuscore group by stuid
) t2
where t1.stuid=t2.stuid and t1.score=t2.maxscore
4.计算每个人的平均成绩
(
select stuid,avg(score) as avgscore from stuscore group by stuid
) t2
where t1.stuid=t2.stuid
5.列出各门课程成绩最好的学生
(
select subject,max(score) as maxscore from stuscore group by subject
) t2
where t1.subject=t2.subject and t1.score=t2.maxscore
6.列出各门课程成绩最好的两位学生
where t1.stuid in
(select top 2 stuscore.stuid from stuscore where subject = t1.subject order by score desc)
order by t1.subject
7.学号 姓名 语文 数学 英语 总分 平均分
sum(case when subject='语文' then score else 0 end) as 语文,
sum(case when subject='数学' then score else 0 end) as 数学,
sum(case when subject='英语' then score else 0 end) as 英语,
sum(score) as 总分,(sum(score)/count(*)) as 平均分
from stuscore
group by stuid,name
order by 总分desc
8.列出各门课程的平均成绩
group by subject
9.列出数学成绩的排名
insert into @tmp select null,name,score,stuid from stuscore where subject='数学' order by score desc
declare @id int
set @id=0;
update @tmp set @id=@id+1,pm=@id
select * from @tmp
order by score desc
insert into @tmp
select name,score,stuid from stuscore where subject='数学' order by score desc
select * from @tmp
10. 列出数学成绩在2-3名的学生
(
select top 2 t2.* from (
select top 3 name,subject,score,stuid from stuscore where subject='数学'
order by score desc
) t2 order by t2.score
) t3 order by t3.score desc
11. 求出李四的数学成绩的排名
insert into @tmp select null,name,score,stuid from stuscore where subject='数学' order by score desc
declare @id int
set @id=0;
update @tmp set @id=@id+1,pm=@id
select * from @tmp where name='李四'
12. 课程 不及格(-59) 良(-80) 优(-100)
(select count(*) from stuscore where score<60 and subject=t1.subject) as 不及格,
(select count(*) from stuscore where score between 60 and 80 and subject=t1.subject) as 良,
(select count(*) from stuscore where score >80 and subject=t1.subject) as 优
from stuscore t1 group by subject
set @s=''
select @s =@s+','+name+'('+convert(varchar(10),score)+'分)' from stuscore where subject='数学'
set @s=stuff(@s,1,1,'')
print '数学:'+@s