An easy problem

An easy problem

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2563    Accepted Submission(s): 1806

Problem Description

In this problem you need to make a multiply table of N * N ,just like the sample out. The element in the i^th row and j^th column should be the product(乘积) of i and j.

 

Input

The first line of input is an integer C which indicate the number of test cases.

Then C test cases follow.Each test case contains an integer N (1<=N<=9) in a line which mentioned above.

 

Output

For each test case, print out the multiply table.

 

Sample Input

2
1
4

 

Sample Output

1
1 2 3 4
2 4 6 8
3 6 9 12
4 8 12 16

#include <stdio.h>
int main( )
{
    int N, T;
    scanf("%d", &T);
    while(T--) {
        scanf("%d", &N);
        int i, j, flag = 0;
        for(i = 1; i <= N; i++) {
            for(j = 1; j <= N; j++) {
                if (!flag)
                printf("%d",i * j), flag = 1;
                else
                printf(" %d",i *j);
            }
            flag = 0;
            puts("");
        }
    }
    return 0;
}

Hint