Oracle query that count connections by minute with start and end times provided

数据结构类似
SQL> select * from t;

B                 E                 N
----------------- ----------------- --------------------
20150106 01:00:02 20150106 01:00:42 A
20150106 01:00:02 20150106 01:00:12 B
20150106 02:01:02 20150106 01:10:03 C
20150106 02:01:07 20150106 02:01:08 D
20150106 02:00:01 20150106 02:00:02 E
20150106 01:00:03 20150106 01:00:07 F

6 rows selected.
 
数据表定义
SQL> @desc t
           Name                            Null?    Type
           ------------------------------- -------- ----------------------------
    1      B                                        DATE
    2      E                                        DATE
    3      N                                        VARCHAR2(10)
 
需求抽象
以分钟为单位统计指定天每分钟内N的个数。
 
思路:
1、每天1440分钟,构造全天的分钟集合
SELECT to_date('20150106 00:00:00' 'yyyy-mm-dd hh24:mi:ss') +
         numtodsinterval (level 'minute') dt
    FROM dual
  CONNECT BY level <= 24 * 60
 
2、左外连接,条件 dt >= begin and dt < end + 1
 
3、需要截取t.begin 和 t.end到分钟
对于begin , trunc(begin,'mi')
对于end   , trunc(end+ numtodsinterval(1, 'minute'),'mi'))  // trunc( end + 1 ,[format])
 
4、按分钟聚合统计
 
 
结果
WITH each_minute AS
 ( SELECT to_date( '20150106 00:00:00' , 'yyyy-mm-dd hh24:mi:ss' ) +
         numtodsinterval (level 'minute') dt
    FROM dual
  CONNECT BY level <= 24 * 60 )
SELECT trunc (em.dt, 'mi') d, count (t.n) cnt
  FROM each_minute em
  LEFT OUTER JOIN t
    ON (em.dt >= trunc (t.b, 'mi'AND em.dt < trunc (t.e+ numtodsinterval (1 'minute'), 'mi' ))
group by trunc(em.dt, 'mi' )
order by 1;
 
简单测试
SQL> WITH each_minute AS
  2   (SELECT to_date('20150106 00:00:00', 'yyyy-mm-dd hh24:mi:ss') +
  3           numtodsinterval(level, 'minute') dt
  4      FROM dual
  5    CONNECT BY level <= 24 * 60)
  6  SELECT trunc(em.dt, 'mi') d, count(t.n) cnt
  7    FROM each_minute em
  8    LEFT OUTER JOIN t
  9      ON (em.dt >= trunc(t.b, 'mi') AND
10         em.dt < trunc(t.e + numtodsinterval(1, 'minute'), 'mi'))
11   where t.n is not null   -- no need for 1440,just for test.
12   group by trunc(em.dt, 'mi')
13   order by 1;

D                        CNT
----------------- ----------
20150106 01:00:00          3
20150106 02:00:00          1
20150106 02:01:00          1
posted @ 2015-06-30 05:51  syksky  阅读(158)  评论(0编辑  收藏  举报