[YTU]_2390( 抽象一个形状类)
题目描述
阮宝同学期待着暑假来临,知道C++不好好复习麻烦不小。没有多态性,那就不叫面向对象,老师不划重点也能猜到。嘿嘿,自己做个经典题,怎么变题也不怕。老湿,再难的题还有木有?
输入
输入四个数,前两个是矩形的长和宽,后两个是三角形的底边长和高。
输出
分两行输出两个数,第一个是矩形的面积,第二个是三角形的面积。
样例输入
3.5 6.4
3.5 6.4
样例输出
22.4 11.2#include <iostream> using namespace std; class Shape { public: virtual double area()const=0; }; class Rectangle:public Shape { public: Rectangle(double h,double w):height(h),weight(w){} virtual double area()const{return height*weight;} private: double height, weight; }; class Triangle:public Shape { public: Triangle(double w,double h):weight(w),height(h){} virtual double area()const{return 0.5*weight*height;} private: double weight; double height; }; int main() { double a,b; cin>>a>>b; Rectangle r(a,b); Shape *s1=&r; cout<<s1->area()<<endl; double w,h; cin>>w>>h; Triangle t(w,h); Shape &s2=t; cout<<s2.area()<<endl; return 0; }