xmlrpc 第一次实现

    package demo.xmlrpc;  
      
    import java.io.IOException;  
    import java.net.MalformedURLException;  
    import java.net.URL;  
    import java.util.Vector;  
      
    import org.apache.xmlrpc.XmlRpcException;  
    import org.apache.xmlrpc.client.XmlRpcClient;  
    import org.apache.xmlrpc.client.XmlRpcClientConfigImpl;  
      
    public class Client1 {  
      
        public static void main(String[] args) {  
      
            try {  
                // 客户端配置对象,并且设置用户名密码  
                XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl();
                config.setServerURL(new URL(  
    "http://218.4.33.65:8029/ResourceManagerApiService/GetCurrentReservations")); //需要根据自己的具体情况修改url  
                config.setBasicUserName("***");
                config.setBasicPassword("****");
      
                //创建一个XmlRpcClient对象,并给它绑定一个配置对象  
                XmlRpcClient client = new XmlRpcClient();  
                client.setConfig(config);  
                  
                // 创建参数集合             
                Vector<String> params= new Vector<String>();  
                params.addElement("****");  
                
                String result=(String)client.execute("reservationOwner",params);  
      
                System.out.println(result);  
      
            } catch (MalformedURLException e) {  
                System.out.println(e.toString());  
            } catch (XmlRpcException e) {  
                System.out.println(e.toString());  
            } catch (IOException e) {  
                e.printStackTrace();  
            }  
      
        }  
      
    } 

 

接口要求

 

目前运行结果

 

org.apache.xmlrpc.client.XmlRpcHttpTransportException: HTTP server returned unexpected status: Unauthorized

百度查看之后是 401 无权限

不过参数传参如何传还是没搞明白

 

posted @ 2017-01-11 11:58  stuwq  阅读(466)  评论(0编辑  收藏  举报