sigmod函数求导

sigmod函数:

\[f(z)=\frac{1}{1+e^{-z}} \]

求导:

\[\frac{\partial f(z)}{\partial z}=\frac{-1*-1*e^{-z}}{(1+e^{-z})^2} =\frac{e^{-z}}{(1+e^{-z})^2} =\frac{1+e^{-z}-1}{(1+e^{-z})^2} =\frac{1}{1+e^{-z}}-\frac{1}{(1+e^{-z})^2} =\frac{1}{1+e^{-z}}(1-\frac{1}{1+e^{-z}}) \]

\[=f(z)(1-f(z)) \]

posted @ 2019-06-18 18:12  JohnRed  阅读(957)  评论(0编辑  收藏  举报