使用递归方法穿越迷宫

这是我在书上看到的一个用递归方法做的一个穿越迷宫的程序,发来大家共同学习

public class MazeSearch
{
public static void main(String [] args)
{
Maze labyrinth
= new Maze();
System.out.println(labyrinth);
if(labyrinth.traverse(0,0))
System.out.println(
"The maze was successfully tranversed!");
else
System.out.println(
"There is no possible path.");

System.out.println(labyrinth);
}
}

  

public class Maze
{
private final int TRIED = 3;
private final int PATH = 7;
private int[][] grid = {
{
1,1,1,0,1,1,1,0,0,1,1,1,1},
{
1,0,1,1,1,0,1,1,1,1,0,0,1},
{
0,0,0,0,1,0,1,0,1,0,1,0,0},
{
1,1,1,0,1,0,1,0,1,0,1,1,1},
{
1,0,1,0,0,0,0,1,1,1,0,0,1},
{
1,0,1,1,1,1,1,1,0,1,1,1,1},
{
1,0,0,0,0,0,0,0,0,0,0,0,0},
{
1,1,1,1,1,1,1,1,1,1,1,1,1}
};
public boolean traverse(int row,int column)
{
boolean done = false;
if(valid(row,column))
{
grid[row][column]
= TRIED;

if(row == grid.length-1&&column==grid[0].length-1)
done
= true;
else
{
done
= traverse(row+1,column);
if(!done)
done
= traverse(row,column+1);
if(!done)
done
= traverse(row-1,column);
if(!done)
done
= traverse(row,column-1);
}
if(done)
grid[row][column]
= PATH;

}
return done;
}
private boolean valid (int row,int column)
{
boolean result = false;
if(row>=0&&row<grid.length&&column>=0&&column<grid[row].length)
if(grid[row][column]==1)
result
= true;
return result;
}
public String toString ()
{
String result
= "\n";
for(int row = 0;row<grid.length;row++)
{
for (int column=0;column<grid[row].length ;column++ )
result
+= grid[row][column]+"";
result
+= "\n";

}
return result;
}

}

  这是运行结果

刚开始学习java,水平不高欢迎指点

posted on 2011-09-01 17:13  shys  阅读(512)  评论(0编辑  收藏  举报

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