jianupc

 

手动部署servlet

1.编写servlet，在tomcat\webapps目录下新建文件Test，Test目录如下

Test

|

classes   web.xml

|

test01

|

Servletfirst.java

Servletfirst.java文件内容如下

 1 package test01;
 2 
 3 import java.io.IOException;
 4 import java.io.PrintWriter;
 5 
 6 import javax.servlet.ServletException;
 7 import javax.servlet.http.HttpServlet;
 8 import javax.servlet.http.HttpServletRequest;
 9 import javax.servlet.http.HttpServletResponse;
10 
11 public class Servletfirst extends HttpServlet {
12     public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException,IOException {
13         PrintWriter out=response.getWriter();
14         out.println("Hello world!");
15     }
16     public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException,IOException {
17         doGet(request, response);
18     }
19 }
View Code

2.在命令行模式下往classpath变量中添加servlet-api.jar的路径，例如set classpath=%classpath%;E:\Program Files\tomcat\lib\servlet-api.jar
进入Servletfirst.java的目录，编译.java文件生成.class文件，javac -d . Servletfirst.java

3.配置web.xml文件

1 <servlet>
2         <servlet-name>Servletfirst</servlet-name>
3         <servlet-class>test01.Servletfirst</servlet-class>
4     </servlet>
5     <servlet-mapping>
6     <servlet-name>Servletfirst</servlet-name>
7     <url-pattern>/hello</url-pattern>
8     </servlet-mapping>
View Code

4.在tomcat\bin目录下执行startup.bat开启服务器
5.在浏览器地址栏里输入http://localhost:8080/Test/hello就能访问servlet了。

 

posted on 2014-09-18 10:16  shijianupc  阅读(257)  评论(0)  编辑  收藏  举报

导航