hdu_1036(取整和格式控制)
题意很简单，求平均时间
复习一下如何取整
(int) fl 是直接向下取整 == floor(fl)
向上取整 (int)(fl+1) == ceil(fl)
四舍五入 (int)(fl+0.5)
技巧：输入时候决定什么时候读入int，什么时候读入char有时候可以省很多事情
代码：
1 #include<cstdio> 2 #include<cstring> 3 #include<algorithm> 4 using namespace std; 5 int hour, minutes, second; 6 bool fl;int t; 7 char tm[7]; 8 void solve(){ 9 if(tm[0]=='-'){fl = 0; return;} 10 hour += tm[0]-'0'; 11 minutes = minutes + (tm[2]-'0')*10+(tm[3]-'0'); 12 second = second + (tm[5]-'0')*10+(tm[6]-'0'); 13 } 14 void pout(){ 15 if(t/100==0) printf(" "); 16 if(t/10==0) printf(" "); 17 printf("%d",t); 18 printf(": %d:",minutes); 19 if(second/10==0) printf("0"); 20 printf("%d min/km\n",second); 21 } 22 int main() 23 { 24 int n; double d; 25 char tt[3]; 26 while(~scanf("%d%lf",&n,&d)) 27 { 28 while(~scanf("%d",&t)){ 29 hour = 0, minutes = 0; second = 0; 30 fl = 1; 31 for(int i = 0; i < n; i++){ 32 scanf("%s",&tm); 33 solve(); 34 } 35 if(fl==0){ 36 if(t/100==0) printf(" "); 37 if(t/10==0) printf(" "); 38 printf("%d",t); 39 printf(": -\n"); 40 continue; 41 } 42 double allminutes = hour*60+minutes+(double)second/60; 43 //printf("min = %lf\n",allminutes); 44 allminutes /= d; 45 minutes = (int)allminutes; 46 second =(int)((allminutes-(int)allminutes)*60+0.5); 47 if(second==60){ 48 second = 0; 49 minutes ++; 50 } 51 pout(); 52 } 53 } 54 return 0; 55 }
