递归实现N级目录

// data
var menuList = [
    {
        Name: '1级1',
        id: '1'
    },
    {
        Name: '1级2',
        id: '2',
    },
    {
        Name: '1级1-1',
        id: '3',
        parent: '1'
    },
    {
        Name: '1级2-1',
        id: '4',
        parent: '2'
    },
    {
        Name: '好多级',
        id: '5',
        parent: '3',
    },
    {
        Name: '好多级2',
        id: '6',
        parent: '5',
    }
];    
function sonMenu(obj, arr) {
    var child = []
    for (var i = 0; i < arr.length; i++) {
        if (arr[i].parent === obj.id) {
            sonMenu(arr[i], arr);
            child.push(arr[i]);
        }
    }
    if (child.length > 0) {
        obj.children = child;
    }
    return obj;
}


function menuInit(data) {
    let ptree = [];
    for (var i = 0; i < data.length; i++) {
        if (!data[i].parent) {//获取父元素
            let o = sonMenu(data[i], data);
            ptree.push(o);
        }
    }
    return ptree;
}

 

posted @ 2019-03-27 22:04  安全佬  阅读(215)  评论(0编辑  收藏  举报