loj2280 「FJOI2017」矩阵填数

状压 dp。参考there

#include <algorithm>
#include <iostream>
#include <cstring>
#include <cstdio>
using namespace std;
typedef long long ll;
int T, h, w, m, n, dp[1055][1055], qx[55], qy[55], dx, dy, blc, sss[505], bel[505];
int maxn[505];
const int mod=1000000007;
struct Node{
	int xu, yu, xv, yv, vv;
}nd[15];
bool f(int x, int y, int i){
	return (x>nd[i].xu && y>nd[i].yu && x<=nd[i].xv && y<=nd[i].yv);
}
int ksm(int a, int b){
	int re=1;
	while(b){
		if(b&1)	re = (ll)re * a % mod;
		a = (ll)a * a % mod;
		b >>= 1;
	}
	return re;
}
int main(){
	cin>>T;
	while(T--){
		memset(dp, 0, sizeof(dp));
		memset(bel, 0, sizeof(bel));
		dx = dy = blc = 0;
		scanf("%d %d %d %d", &h, &w, &m, &n);
		for(int i=1; i<=n; i++){
			scanf("%d %d %d %d %d", &nd[i].xu, &nd[i].yu, &nd[i].xv, &nd[i].yv, &nd[i].vv);
			nd[i].xu--; nd[i].yu--;
			qx[++dx] = nd[i].xu; qx[++dx] = nd[i].xv;
			qy[++dy] = nd[i].yu; qy[++dy] = nd[i].yv;
		}
		qx[++dx] = 0;
		qy[++dy] = 0;
		qx[++dx] = h;
		qy[++dy] = w;
		sort(qx+1, qx+1+dx);
		sort(qy+1, qy+1+dy);
		dx = unique(qx+1, qx+1+dx) - (qx + 1);
		dy = unique(qy+1, qy+1+dy) - (qy + 1);
		for(int i=2; i<=dx; i++)
			for(int j=2; j<=dy; j++){
				blc++;
				sss[blc] = (qx[i] - qx[i-1]) * (qy[j] - qy[j-1]);
				maxn[blc] = m;
				for(int k=1; k<=n; k++)
					if(f(qx[i], qy[j], k))
						maxn[blc] = min(maxn[blc], nd[k].vv);
				for(int k=1; k<=n; k++)
					if(f(qx[i], qy[j], k) && maxn[blc]==nd[k].vv)
						bel[blc] |= 1<<(k-1);
			}
		dp[0][0] = 1;
		for(int i=1; i<=blc; i++){
			int fai=ksm(maxn[i]-1, sss[i]);
			int suc=(ksm(maxn[i], sss[i])-fai+mod)%mod;
			for(int j=0; j<(1<<n); j++){
				dp[i][j] = (dp[i][j] + (ll)dp[i-1][j]*fai%mod) % mod;
				dp[i][j|bel[i]] = (dp[i][j|bel[i]] + (ll)dp[i-1][j]*suc%mod) % mod;
			}
		}
		printf("%d\n", dp[blc][(1<<n)-1]);
	}
	return 0;
}
posted @ 2018-04-16 11:11  poorpool  阅读(185)  评论(0编辑  收藏  举报