leetcode 237. Delete Node in a Linked List

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237. Delete Node in a Linked List

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Total Accepted: 62658 Total Submissions: 143216 Difficulty: Easy

 

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

 

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/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
 // 参考 http://blog.csdn.net/sunao2002002/article/details/47083975
 // 从链表中，删除指定的节点，但又没有给出前指针，所以先交换当前节点和下一节点的值，然后删除下一节点即可。代码如下：
class Solution {
public:
    void deleteNode(ListNode* node) {
        if(node == NULL || node->next == NULL) return;
        node->val = node->next->val;
        node->next = node->next->next;
    }
};