用requests库爬取猫眼电影Top100
这里需要注意一下,在爬取猫眼电影Top100时,网站设置了反爬虫机制,因此需要在requests库的get方法中添加headers,伪装成浏览器进行爬取
import requests from requests.exceptions import RequestException from multiprocessing import Pool import re import json def get_one_page(url): try: headers = {"User-Agent": "Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/68.0.3440.106 Safari/537.36"} response = requests.get(url, headers=headers) if response.status_code == 200: return response.text except RequestException: return None def parse_one_page(html): pattern = re.compile('<dd>.*?board-index.*?>(\d+)</i>.*?data-src="(.*?)".*?name"><a' +'.*?>(.*?)</a>.*?star">(.*?)</p>.*?releasetime">(.*?)</p>' +'.*?integer">(.*?)</i>.*?fraction">(.*?)</i>.*?</dd>', re.S) items = re.findall(pattern, html) for item in items: yield { 'index': item[0], 'image': item[1], 'title': item[2], 'actor': item[3].strip()[3:], 'time': item[4].strip()[5:], 'score': item[5] + item[6] } def write_to_file(content): with open('result.txt', 'a', encoding='utf-8') as f: f.write(json.dumps(content, ensure_ascii=False) + '\n') f.close() def main(offset): url = "http://maoyan.com/board/4?offset=" + str(offset) html = get_one_page(url) for item in parse_one_page(html): print(item) write_to_file(item) if __name__ == '__main__': pool = Pool() pool.map(main, [i*10 for i in range(10)])
运行结果如下: