UVA 10340 - All in All 水~

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Problem E

All in All

Input: standard input

Output: standard output

Time Limit: 2 seconds

Memory Limit: 32 MB

You have devised a new encryption technique whichencodes a message by inserting between its characters randomly generatedstrings in a clever way. Because of pending patent issues we will not discussin detail how the strings are generated and inserted into the original message.To validate your method, however, it is necessary to write a program thatchecks if the message is really encoded in the final string.

Given two strings s and t, you haveto decide whether s is a subsequence oft, i.e. if you can removecharacters fromt such that the concatenation of the remainingcharacters iss.

Input Specification

The input contains several testcases. Each isspecified by two strings s, t of alphanumeric ASCII characters separatedby whitespace. Input is terminated by EOF.

Output Specification

For each test case output, if s is asubsequence of t.

Sample Input

sequence subsequence

person compression

VERDI vivaVittorioEmanueleReDiItalia

caseDoesMatter CaseDoesMatter

SampleOutput

Yes

No

Yes

No

题解：

水题哇~直接扫描一遍数组就好了，出现RE的话把数组开大就好了~

代码：

#include<cstdio>
#include<cstring>
const int MAXN=500000;
char a[MAXN],b[MAXN];
int main()
{
	while(scanf("%s%s",b,a)!=EOF)
	{
		int lena,lenb;
		lena=strlen(a);
		lenb=strlen(b);
		bool ok=true;
		int i=0,j=0;
		for(;i<lena&&j<lenb;i++)
			if(a[i]==b[j])
				j++;
		if(j!=lenb)
			ok=false;
		printf("%s\n",ok==true?"Yes":"No");
	}
}