JS的各种排序算法实现

Javascript的各种排序算法实现,转自某位牛人,具体地址已不记得。

 

// ---------- 一些排序算法
var Sort = {}
Sort.prototype = {
      // 利用sort进行排序  
       systemSort:function(array){  
          return array.sort(function(a, b){  
              return a - b;  
          });  
      },
      
      // 冒泡排序  
      bubbleSort:function(array){  
          var i = 0, len = array.length,  
              j, d;  
          for(; i<len; i++){  
              for(j=0; j<len; j++){  
                  if(array[i] < array[j]){  
                      d = array[j];  
                      array[j] = array[i];  
                      array[i] = d;  
                  }  
              }  
          }  
          return array;  
      },
      
      // 快速排序  
      quickSort:function(array){  
          //var array = [8,4,6,2,7,9,3,5,74,5];  
          //var array =[0,1,2,44,4,324,5,65,6,6,34,4,5,6,2,43,5,6,62,43,5,1,4,51,56,76,7,7,2,1,45,4,6,7];  
          var i = 0;  
          var j = array.length - 1;  
          var Sort = function(i, j){  
              // 结束条件  
              if(i == j ){ return };
              var key = array[i];  
              var tempi = i; // 记录开始位置  
              var tempj = j; // 记录结束位置  
              
              while(j > i){  
                  // j <<-------------- 向前查找  
                  if(array[j] >= key){  
                      j--;  
                  }else{  
                      array[i] = array[j]  
                      //i++ ------------>>向后查找  
                      while(j > ++i){  
                          if(array[i] > key){  
                              array[j] = array[i];  
                              break;  
                          }  
                      }  
                  }  
              }
              // 如果第一个取出的 key 是最小的数  
              if(tempi == i){  
                  Sort(++i, tempj);  
                  return ;  
              }
              // 最后一个空位留给 key  
              array[i] = key;  
              // 递归  
              Sort(tempi, i);  
              Sort(j, tempj);  
          }  
          Sort(i, j);
          return array;  
      },  
        
      // 插入排序  
      insertSort:function(array){  
          // http://baike.baidu.com/image/d57e99942da24e5dd21b7080  
          // http://baike.baidu.com/view/396887.htm  
          // var array = [0,1,2,44,4,324,5,65,6,6,34,4,5,6,2,43,5,6,62,43,5,1,4,51,56,76,7,7,2,1,45,4,6,7];  
          var i = 1, j, temp, key, len = array.length;
          for(; i < len; i++){  
              temp = j = i;  
              key = array[j];  
              while(--j > -1){  
                  if(array[j] > key){  
                      array[j+1] = array[j];  
                  }else{
                      break;
                  }
              }
              array[j+1] = key;  
          }
          return array;  
      },  
        
      // 希尔排序  
      //Jun.array.shellSort(Jun.array.df(10000));  
      shellSort:function(array){  
          // http://zh.wikipedia.org/zh/%E5%B8%8C%E5%B0%94%E6%8E%92%E5%BA%8F  
          // var array = [13,14,94,33,82,25,59,94,65,23,45,27,73,25,39,10];
          // var tempArr = [1750, 701, 301, 132, 57, 23, 10, 4, 1];   
          // reverse() 在维基上看到这个最优的步长 较小数组  
          var tempArr = [1031612713, 217378076, 45806244, 9651787, 2034035, 428481, 90358, 19001, 4025, 836, 182, 34, 9, 1]  
              //针对大数组的步长选择  
          var i = 0;  
          var tempArrtempArrLength = tempArr.length;  
          var len = array.length;  
          var len2 =  parseInt(len/2);  
            
          for(;i < tempArrLength; i++){  
              if(tempArr[i] > len2){  
                  continue;  
              }
              tempSort(tempArr[i]);  
          }
          // 排序一个步长  
          function tempSort(temp){  
              //console.log(temp) 使用的步长统计  
              var i = 0, j = 0, f, tem, key;  
              var tempLen = len%temp > 0 ?  parseInt(len/temp) + 1 : len/temp;   
              
              for(;i < temp; i++){// 依次循环列  
   
                  for(j=1;/*j < tempLen && */temp * j + i < len; j++){
                        //依次循环每列的每行  
                      tem = f = temp * j + i;  
                      key = array[f];  
   
                      while((tem-=temp) >= 0){  
                            // 依次向上查找
                          if(array[tem] > key){
                              array[tem+temp] = array[tem];
                          }else{
                              break;
                          }
                      }
                      array[tem + temp ] = key;
                  }
              }
          }
          return array;
      }
}

posted on 2013-09-12 11:17  midii  阅读(512)  评论(1编辑  收藏  举报

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