虚基类构造函数的调用
#include <iostream>
using namespace std;
class base
{protected:
int x;
public:
base(int x1)
{x=x1;
cout<<"constructing base,x="<<x<<endl;
}
~base()
{cout<<"disconstructing base"<<endl;
}
};
class base1:virtual public base
{int y;
public:
base1(int x1,int y1):base(x1)
{y=y1;
cout<<"constructing base1,y="<<y<<endl;
}
};
class base2:virtual public base
{int z;
public:
base2(int x1,int z1):base(x1)
{z=z1;
cout<<"constructing base2,z="<<z<<endl;
}
~base2()
{cout<<"disconstructing base2"<<endl;
}
};
class derived:public base1,public base2
{int xyz;
public:
derived(int x1,int y1,int z1,int xyz1):base(x1),base1(x1,y1),base2(x1,z1)
{xyz=xyz1;
cout<<"constructing derived xyz="<<xyz<<endl;
}
~derived()
{cout<<"disconstructing derived"<<endl;
}
};
int main()
{derived obj(1,2,3,4);
return 0;
}
以上代码，简要概括虚基类构造函数的调用 结果如下
派生类的构造函数首先直接调用base的构造函数，而base1，base2，不再去调用，
（c++未调用不分配内存空间）
