链表_leetcode147

# Definition for singly-linked list.
class ListNode(object):
def __init__(self, x):
self.val = x
self.next = None

class Solution(object):
def insertionSortList(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""

if not head or not head.next:
return head


dummyHead = ListNode(0)
dummyHead.next = head
pre = dummyHead

cur = head.next



p = head
p.next = None

while cur:

while p:

if cur.val < p.val:
nextCur = cur.next

cur.next = p
pre.next = cur
cur = nextCur

pre = dummyHead
p = pre.next

break
else:
pre = p
p = p.next


if not p:

nextCur = cur.next
pre.next = cur
cur.next = None

cur = nextCur
pre = dummyHead
p = pre.next




return dummyHead.next


def creatList(self,l):
dummyHead = ListNode(0)

pre = dummyHead

for i in l:
pre.next = ListNode(i)
pre = pre.next

return dummyHead.next


def printList(self,head):
cur = head

while cur:
print cur.val
cur = cur.next




l1 = [4,2,1,3]

s = Solution()

head = s.creatList(l1)

s.printList(head)

head = s.insertionSortList(head)

s.printList(head)
posted @ 2019-03-19 10:57  AceKo  阅读(120)  评论(0编辑  收藏  举报