动态规划_leetcode70

class Solution(object):


def climbStairs(self, n):
"""
:type n: int
:rtype: int
"""

self.memo = [-1 for i in range(n+1)]

return self.calcWays1(n)

def calcWays1(self,n):
if n == 1:
return 1
if n == 2:
return 2

else:
return self.climbStairs(n-1) + self.climbStairs(n-2)

def calcWays2(self, n):
if n == 0 or n == 1:
return 1
if self.memo[n] == -1:
self.memo[n] = self.calcWays2(n-1) + self.calcWays2(n-2)


def calcWays3(self, n):
memo = [-1 for i in range(n+1)]

memo[1] = 1
memo[2] = 2


for i in range(3,n+1):
memo[i] = memo[i-1] + memo[i-2]


return memo[n]

posted @ 2019-03-17 12:44  AceKo  阅读(167)  评论(0编辑  收藏  举报