[LeetCode#181]Employees Earning More Than Their Managers
The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 80000 | 4 | | 3 | Sam | 60000 | NULL | | 4 | Max | 90000 | NULL | +----+-------+--------+-----------+ Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager. +----------+ | Employee | +----------+ | Joe | +----------+
本题是有一张表Employee,表中包含employee和他们的manager,分别有name列、Salary列和ManagerId列,需要找出employee比自己的manager领的薪水高的employee:
解法一:
select e1.Name as employee from employee e1,employee e2 where e1.ManagerId = e2.Id and e1.Salary > e2.Salary;
解法二:
select e1.Name as employee from employee e1 join employee e2 on e1.ManagerId = e2.Id where e1.Salary > e2.Salary;
作者:薛定谔的ハチ公
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