Flatten Binary Tree to Linked List
Given a binary tree, flatten it to a linked list in-place.
For example, Given
1 / \ 2 5 / \ \ 3 4 6
The flattened tree should look like:
1 \ 2 \ 3 \ 4 \ 5 \ 6
Hints:
If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order traversal
思想: 如 Hints.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ TreeNode* getPreNode(TreeNode *root) { if(root == NULL) return NULL; while(root->right) root = root->right; return root; } class Solution { public: void flatten(TreeNode *root) { if(root == NULL) return; TreeNode *pre = getPreNode(root->left); if(pre) { pre->right = root->right; root->right = root->left; root->left = NULL; } flatten(root->right); } };