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Reorder List

           Given a singly linked list L: L0L1→…→Ln-1Ln, reorder it to: L0LnL1Ln-1L2Ln-2→…

You must do this in-place without altering the nodes' values.

For example, Given {1,2,3,4}, reorder it to {1,4,2,3}.

说明:分三步,1。从中间分开,成两部分。2,后半部分链表逆置。3.插入合并。

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void reorderList(ListNode *head) {
        if(head == NULL) return; 
        ListNode *p1, *p2, *p3, *head2;
        p1 = p2 = head;
        while(p2->next && p2->next->next) {
            p1 = p1->next;
            p2 = p2->next->next;
        }
        head2 = p1->next; p1 = p1->next = NULL;
        p2 = head2;
        while(p2) {
            p3 = p2->next;
            p2->next = p1;
            p1 = p2;
            p2 = p3;
        }
        head2 = p1; p1 = head;
        while(head2 && p1) {
            p2 = head2->next;
            head2->next = p1->next;
            p1->next = head2;
            head2 = p2;
            p1 = p1->next->next;
        }
        
        
    }
};

 

posted on 2014-08-10 01:23  进阶之路  阅读(185)  评论(0编辑  收藏  举报