leetcode-383. Ransom Note
383. Ransom Note
Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.
Each letter in the magazine string can only be used once in your ransom note.
Note:
You may assume that both strings contain only lowercase letters.
canConstruct("a", "b") -> false canConstruct("aa", "ab") -> false canConstruct("aa", "aab") -> true
这题求 ransomNote 中的字母是否都在 magazine 中,不要求顺序一致
所以直接将 magazine 转换为 StringBuffer ,看 ransomNote 的字符的下标是否不为-1,存在即删除。不存在即返回false。
solution:
class Solution { public boolean canConstruct(String ransomNote, String magazine) { StringBuffer Strb = new StringBuffer(magazine); for (int i = 0; i < ransomNote.length(); i++) { int n = Strb.indexOf(String.valueOf(ransomNote.charAt(i))); if(n!=-1) Strb.deleteCharAt(n); else return false; } return true; } }