[LeetCode] 232. Implement Queue using Stacks 用栈来实现队列
Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
Notes:
- You must use only standard operations of a stack -- which means only
push to top
,peek/pop from top
,size
, andis empty
operations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
用栈来实现队列,对比类似题目225. Implement Stack using Queues 是反过来用。
Java:
class MyQueue { Stack<Integer> temp = new Stack<Integer>(); Stack<Integer> value = new Stack<Integer>(); // Push element x to the back of queue. public void push(int x) { if(value.isEmpty()){ value.push(x); }else{ while(!value.isEmpty()){ temp.push(value.pop()); } value.push(x); while(!temp.isEmpty()){ value.push(temp.pop()); } } } // Removes the element from in front of queue. public void pop() { value.pop(); } // Get the front element. public int peek() { return value.peek(); } // Return whether the queue is empty. public boolean empty() { return value.isEmpty(); } }
Python:
class Queue: # initialize your data structure here. def __init__(self): self.A, self.B = [], [] # @param x, an integer # @return nothing def push(self, x): self.A.append(x) # @return an integer def pop(self): self.peek() return self.B.pop() # @return an integer def peek(self): if not self.B: while self.A: self.B.append(self.A.pop()) return self.B[-1] # @return an boolean def empty(self): return not self.A and not self.B
C++:
class Queue { public: // Push element x to the back of queue. void push(int x) { stack<int> tmp; while (!s.empty()) { tmp.push(s.top()); s.pop(); } s.push(x); while (!tmp.empty()) { s.push(tmp.top()); tmp.pop(); } } // Removes the element from in front of queue. void pop(void) { s.pop(); } // Get the front element. int peek(void) { return s.top(); } // Return whether the queue is empty. bool empty(void) { return s.empty(); } private: stack<int> s; };
C++:
class Queue { public: // Push element x to the back of queue. void push(int x) { _new.push(x); } void shiftStack() { if (_old.empty()) { while (!_new.empty()) { _old.push(_new.top()); _new.pop(); } } } // Removes the element from in front of queue. void pop(void) { shiftStack(); if (!_old.empty()) _old.pop(); } // Get the front element. int peek(void) { shiftStack(); if (!_old.empty()) return _old.top(); return 0; } // Return whether the queue is empty. bool empty(void) { return _old.empty() && _new.empty(); } private: stack<int> _old, _new; };
类似题目:
[LeetCode] 225. Implement Stack using Queues 用队列来实现栈