leetcode-1比特与2比特字符

def isOneBitCharacter(bits):
"""
:type bits: List[int]
:rtype: bool
"""
while len(bits)>2:
if bits[0]==1:
bits=bits[2:]
else:
bits=bits[1:]
if bits==[1,0]:
return False
elif bits==[0,0] or bits==[0]:
return True


res=isOneBitCharacter([1,1,1,1,1,0,0,0,0,1,1,1,1,0])
print(res)
posted @ 2018-08-31 15:17  李不搭  阅读(298)  评论(0编辑  收藏  举报