Leetcode 138: Copy List with Random Pointer

A linked list is given such that each node contains an additional random pointer which could point to any node in the list or null.

Return a deep copy of the list.

 

 1 /**
 2  * Definition for singly-linked list with a random pointer.
 3  * public class RandomListNode {
 4  *     public int label;
 5  *     public RandomListNode next, random;
 6  *     public RandomListNode(int x) { this.label = x; }
 7  * };
 8  */
 9 public class Solution {
10     public RandomListNode CopyRandomList(RandomListNode head) {
11         if (head == null) return null;
12         
13         RandomListNode newHead = new RandomListNode(head.label), cur = head, newCur = newHead;
14         
15         var dict = new Dictionary<RandomListNode, RandomListNode>();
16         dict[head] = newHead;
17         
18         while (cur.next != null)
19         {
20             var n = new RandomListNode(cur.next.label);
21             dict[cur.next] = n;
22             newCur.next = n;
23             cur = cur.next;
24             newCur = newCur.next;
25         }
26         
27         cur = head;
28         newCur = newHead;
29         
30         while (cur != null)
31         {
32             if (cur.random != null && dict.ContainsKey(cur.random))
33             {
34                 newCur.random = dict[cur.random];
35             }
36             
37             cur = cur.next;
38             newCur = newCur.next;
39         }
40         
41         return newHead;
42     }
43 }

 

posted @ 2017-11-22 06:24  逸朵  阅读(94)  评论(0编辑  收藏  举报