简单的递归函数

# 指定数的阶乘
def sum(n):
if n==1:
return n
else:
return n*sum(n-1)
num=sum(5)
print(num)

# 阶乘递归求和
def total_sum(m):
total=0
for i in range(1,m+1):
def sum(n):
if n==1:
return n
else:
return n*sum(n-1)
total+=sum(i)
return total
num=total_sum(5)
print(num)
posted @ 2019-09-09 09:30  wxl106  阅读(327)  评论(0编辑  收藏  举报