HDU 1233 还是畅通工程 (Kruscal 最小生成树)
文章作者:ktyanny 文章来源:ktyanny 转载请注明,谢谢合作。
ktyanny:很简单吧这道题目,中文题目+Kruscal最小生成树算法,很水的题目我就不多说什么了。
/*
by ktyanny
2009.12.14
*/
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
const int MAX = 105;
typedef struct
{
int a, b;
}point;
point v[MAX];
typedef struct
{
int x, y;
int w;
}edge;
const int MAXN = 50005;
edge e[MAXN];
int ans;
int rank[MAXN];
int pa[MAXN];
void make_set(int x)
{
pa[x] = x;
rank[x] = 0;
}
int find_set(int x)
{
if(x != pa[x])
pa[x] = find_set(pa[x]);
return pa[x];
}
/*按秩合并x,y所在的集合*/
void union_set(int x, int y, int w)
{
x = find_set(x);
y = find_set(y);
if(x == y)return ;
ans += w;
if(rank[x] > rank[y])/*让rank比较高的作为父结点*/
{
pa[y] = x;
}
else
{
pa[x] = y;
if(rank[x] == rank[y])
rank[y]++;
}
}
int cmp(const void *a, const void *b)
{
return ( (*(edge *)a).w > (*(edge *)b).w ) ? 1 : -1;
}
int main()
{
int n, i, j, x, y, k;
while(scanf("%d", &n) && n)
{
k = n * (n-1) / 2;
j = 0;
for(i = 0; i < k; i++)
{
scanf("%d%d%d", &e[j].x, &e[j].y, &e[j].w);
j++;
}
for(i = 0; i <= n; i++)
make_set(i);
qsort(e, j, sizeof(e[0]), cmp);
/*Kruscal过程求最小生成树*/
ans = 0.0;
for(i = 0; i < j; i++)
{
x = find_set(e[i].x);
y = find_set(e[i].y);
if(x != y)
union_set(x, y, e[i].w);
}
printf("%d\n", ans);
}
return 0;
}
by ktyanny
2009.12.14
*/
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
const int MAX = 105;
typedef struct
{
int a, b;
}point;
point v[MAX];
typedef struct
{
int x, y;
int w;
}edge;
const int MAXN = 50005;
edge e[MAXN];
int ans;
int rank[MAXN];
int pa[MAXN];
void make_set(int x)
{
pa[x] = x;
rank[x] = 0;
}
int find_set(int x)
{
if(x != pa[x])
pa[x] = find_set(pa[x]);
return pa[x];
}
/*按秩合并x,y所在的集合*/
void union_set(int x, int y, int w)
{
x = find_set(x);
y = find_set(y);
if(x == y)return ;
ans += w;
if(rank[x] > rank[y])/*让rank比较高的作为父结点*/
{
pa[y] = x;
}
else
{
pa[x] = y;
if(rank[x] == rank[y])
rank[y]++;
}
}
int cmp(const void *a, const void *b)
{
return ( (*(edge *)a).w > (*(edge *)b).w ) ? 1 : -1;
}
int main()
{
int n, i, j, x, y, k;
while(scanf("%d", &n) && n)
{
k = n * (n-1) / 2;
j = 0;
for(i = 0; i < k; i++)
{
scanf("%d%d%d", &e[j].x, &e[j].y, &e[j].w);
j++;
}
for(i = 0; i <= n; i++)
make_set(i);
qsort(e, j, sizeof(e[0]), cmp);
/*Kruscal过程求最小生成树*/
ans = 0.0;
for(i = 0; i < j; i++)
{
x = find_set(e[i].x);
y = find_set(e[i].y);
if(x != y)
union_set(x, y, e[i].w);
}
printf("%d\n", ans);
}
return 0;
}
posted on 2009-12-14 20:34 Ktyanny Home 阅读(805) 评论(0) 编辑 收藏 举报