[MySQL]获取当月每一天

常用使用场景: 统计某个月(某个时间区间)内每一天的数据量 

  1. select date_add(curdate(), interval(cast(help_topic_id as signed integer) - 1) day) day
  2. from mysql.help_topic
  3. where help_topic_id < day(last_day(curdate()))
  4. order by help_topic_id

 

延伸用法: 获取一段时间内的每分钟

  1. set @stime = str_to_date('2018-11-07 08:00', '%Y-%m-%d %H:%i');
  2. set @etime = str_to_date('2018-11-07 08:10', '%Y-%m-%d %H:%i');
  3. select date_add(@stime, interval (cast(help_topic_id as signed integer) - 0) minute) minute
  4. from mysql.help_topic
  5. where help_topic_id <= timestampdiff(minute, @stime, @etime)
  6. order by help_topic_id

 

顺便贴一下oracle的写法

  1. select trunc(sysdate, 'MM') + rownum - 1 day
  2. from dual
  3. connect by rownum <= to_number(to_char(last_day(sysdate), 'dd'))

原文地址:https://blog.csdn.net/reeye_/article/details/83655477
posted @ 2019-07-04 11:22  星朝  阅读(3432)  评论(0编辑  收藏  举报