hdu 1690 Bus System Floyd 求最短路径

题目地址： hdu1690

给你一些车站，问这些车站之间的最“短”（费用最少）路径。

结点个数100 直接用floyd

比较坑的是，给的坐标并没有按升序 还要用abs  wa了很多次

#include<iostream>
#include<cmath>
using namespace std;

#define INF 1000000000000000000LL


typedef long long inta;
int l1,l2,l3,l4,c1,c2,c3,c4;

int n,m;


inta  d[105][105];

inta px[105];


void  init()
{
    for(int i=0;i<n;i++)
        for(int j=0;j<n;j++)
            d[i][j]=INF;
    
    
    for(int i=0;i<n;i++)
        d[i][i]=0;
    
}


void floyd()
{
    for(int k=0;k<n;k++)
     for(int i=0;i<n;i++)
        for(int j=0;j<n;j++)
          if(d[i][k]!=INF&&d[k][j]!=INF)
              d[i][j]=d[i][j]<d[i][k]+d[k][j]?d[i][j]:d[i][k]+d[k][j];
    
          
}


inta calc(inta dist)
{
    if(dist<=l1)  return c1;
    else if(dist<=l2)  return c2;
    else if(dist<=l3)  return c3;
    else if(dist<=l4)  return c4;
    else return INF;
    
    
}
int main()
{
    int cas;
    cin>>cas;
    
    int from,to;
    
    for(int l=0;l<cas;l++)
    {
        cin>>l1>>l2>>l3>>l4>>c1>>c2>>c3>>c4>>n>>m;
        
        for(int i=0;i<n;i++)
            cin>>px[i];
        
        init();   // 初始化
      
        
        
        for(int i=0;i<n;i++)
            for(int j=i+1;j<n;j++)
            {
                d[i][j]=d[i][j]<calc(abs(px[j]-px[i]))?d[i][j]:calc(abs(px[j]-px[i]));
                d[j][i]=d[i][j];
            }
        

        
        
        floyd();
        
        cout<<"Case "<<l+1<<":"<<endl;
        for(int i=0;i<m;i++)
        {
            cin>>from>>to;
            
            if(d[from-1][to-1]!=INF)
            cout<<"The minimum cost between station "<<from<<" and station "<<to<<" is "<<d[from-1][to-1]<<"."<<endl;
            else
            cout<<"Station "<<from<<" and station "<<to<<" are not attainable."<<endl;
        }
        
    
    }
    
}