C# .NET 提交表单POST之另一种方法

System.Net.WebClient WebClientObj = new System.Net.WebClient();
System.Collections.Specialized.NameValueCollection PostVars = new System.Collections.Specialized.NameValueCollection();
PostVars.Add("name", "value");    
try
{
   byte[] byRemoteInfo = WebClientObj.UploadValues(UrlWeb, "POST", PostVars);
   //下面都没用啦，就上面一句话就可以了
   string sRemoteInfo = System.Text.Encoding.Default.GetString(byRemoteInfo);
   //这是获取返回信息
   MessageBox.Show("添加网站成功! ", "OK");
}
catch
{
    MessageBox.Show("添加网站不成功! ", "出错了");
}