[c#算法和数据结构]约瑟夫环问题
问题描述:
设有n个人围坐一圈,现以某个人开始报数,数到m的人出列,接着从出列的下一个人开始重新报数,数到m的人又出列,如此下去,直到所有人都出列为止.按出列顺序输出.
//******************************
//描述:约瑟夫环问题
//类名:Josephas
//作者:洪晓军
//时间:2004-12-27
//******************************
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public class Josephas
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{
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//从第start人开始计数,以alter为单位循环记数出列,总人数为total
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public int [ ] Jose(int total, int alter, int start)
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{
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int i, j, k = 0;
7![](/Images/OutliningIndicators/InBlock.gif)
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//count数组存储按出列顺序的数据,以当结果返回
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int[] count = new int [ total+1];
10![](/Images/OutliningIndicators/InBlock.gif)
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//s数组存储初始数据
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int[] s = new int [ total+1];
13![](/Images/OutliningIndicators/InBlock.gif)
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//对数组s赋初值,第一个人序号为0,第二人为1,依此下去![](/Images/dot.gif)
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for (i = 0; i <total; i++)
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{
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s[i] = i;
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}
19![](/Images/OutliningIndicators/InBlock.gif)
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//按出列次序依次存于数组count中
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for (i = total; i >= 2; i--)
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{
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start = (start + alter - 1) % i;
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if (start == 0)
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start = i;
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count[k] = s[start];
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k++;
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for (j = start + 1; j <= i; j++)
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s[j - 1] = s[j];
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}
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count[k]=s[1];
33![](/Images/OutliningIndicators/InBlock.gif)
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//结果返回
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return count;
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}
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}
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![](/Images/OutliningIndicators/InBlock.gif)
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![](/Images/OutliningIndicators/InBlock.gif)
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![](/Images/OutliningIndicators/InBlock.gif)
![](/Images/dot.gif)
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以上程序在Microsoft Visual Studio .NET 2003 和Visual C# 2005 Express Edition Beta1中均调试通过.