[leetcode]Unique Paths II
Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as
1
and0
respectively in the grid.For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[ [0,0,0], [0,1,0], [0,0,0] ]
算法思路:
跟[leetcode]Unique Paths几乎一样,就加上一个判断好了。
代码如下:
1 public class Solution { 2 public int uniquePathsWithObstacles(int[][] obstacleGrid) { 3 if(obstacleGrid == null || obstacleGrid.length == 0) return 0; 4 int height = obstacleGrid.length; 5 int width = obstacleGrid[0].length; 6 int[][] dp = new int[height][width]; 7 for(int i = 0; i < width;i++){ 8 if(obstacleGrid[0][i] == 0){ 9 dp[0][i] = 1; 10 }else{ 11 break; 12 } 13 } 14 for(int i = 0; i < height;i++){ 15 if(obstacleGrid[i][0] == 0){ 16 dp[i][0] = 1; 17 }else{ 18 break; 19 } 20 } 21 for(int i = 1; i < height; i++){ 22 for(int j = 1; j < width;j++){ 23 if(obstacleGrid[i][j] == 0) 24 dp[i][j] = dp[i - 1][j] + dp[i][j - 1]; 25 } 26 } 27 return dp[height - 1][width - 1]; 28 } 29 }