[leetcode]Path Sum
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:
Given the below binary tree andsum = 22
,5 / \ 4 8 / / \ 11 13 4 / \ \ 7 2 1return true, as there exist a root-to-leaf path
5->4->11->2
which sum is 22.
算法思路:
dfs
代码如下:
1 public class Solution { 2 public boolean hasPathSum(TreeNode root, int sum) { 3 if(root == null) return false; 4 if(root.left == null && root.right == null && root.val == sum) return true; 5 if(root.left != null && hasPathSum(root.left, sum - root.val)) return true; 6 if(root.right != null && hasPathSum(root.right, sum - root.val)) return true; 7 return false; 8 9 } 10 }