[leetcode]Remove Duplicates from Sorted List II
Remove Duplicates from Sorted List II
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.
For example,
Given1->2->3->3->4->4->5
, return1->2->5
.
Given1->1->1->2->3
, return2->3
.
算法思路:
跟[leetcode]Remove Duplicates from Sorted List差不许多,只是加一个前驱节点和标记变量,以便删除重复节点。
1 public class Solution { 2 public ListNode deleteDuplicates(ListNode head) { 3 if(head == null || head.next == null) return head; 4 ListNode hhead = new ListNode(0); 5 hhead.next = head; 6 ListNode one = hhead; 7 ListNode two = head; 8 boolean tag = false; 9 while(two != null){ 10 tag = false; 11 while(two.next != null && two.next.val == two.val) { 12 two = two.next; 13 tag = true; 14 } 15 if(tag){ 16 two = two.next; 17 one.next = two; 18 }else{ 19 one = two; 20 two = two.next; 21 } 22 } 23 return hhead.next; 24 } 25 }