leetcode Convert Sorted Array to Binary Search Tree

利用更有序数组,构造平衡二叉树。

思路,递归,每次中间节点为根节点,然后递归获得左右子树。

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode *fun(vector<int> &num, int start, int end)
    {
        if (start > end) return NULL;
        int mid = (start + end) / 2;
        TreeNode *root = new TreeNode(num[mid]);
        
        root -> left = fun(num, start, mid - 1);
        root -> right = fun(num, mid + 1, end);
        return root;
    }
    TreeNode *sortedArrayToBST(vector<int> &num) {
        return fun(num, 0, num.size() - 1);
    }
};

 

posted on 2014-11-29 21:38  higerzhang  阅读(171)  评论(0编辑  收藏  举报