oracle递归查询子节点

通过子节点向根节点追朔.

select * from persons.dept start with deptid=76 connect by prior paredeptid=deptid

通过根节点遍历子节点(不包含根节点).

select * from persons.dept start with paredeptid=0 connect by prior deptid=paredeptid

通过根节点遍历子节点(包含根节点).

select * from persons.dept start with deptid=0 connect by prior deptid=paredeptid

可通过level 关键字查询所在层次.

select a.*,level from persons.dept a start with paredeptid=0 connect by prior deptid=paredeptid

备注:

start with ...connect by 的用法, start with 后面所跟的就是就是递归的种子。

递归的种子也就是递归开始的地方 connect by 后面的"prior" 如果缺省:则只能查询到符合条件的起始行,并不进行递归查询;

connect by prior 后面所放的字段是有关系的,它指明了查询的方向。

练习: 通过子节点获得顶节点

select FIRST_VALUE(deptid) OVER (ORDER BY LEVEL DESC ROWS UNBOUNDED PRECEDING) AS firstdeptid from persons.dept start with deptid=76 connect by prior paredeptid=deptid

表结构

DEPTID PAREDEPTID NAME

NUMBER NUMBER CHAR (40 Byte)

部门id 父部门id(所属部门id) 部门名称

mysql用法:

SELECT rd.* FROM
(SELECT * FROM sys_depart WHERE PARENT_ID IS NOT NULL) rd,
(SELECT @PARENT_ID := #{departId,jdbcType=VARCHAR}) pd
where FIND_IN_SET( PARENT_ID, @PARENT_ID ) > 0
union all
select * from sys_depart where id = #{departId,jdbcType=VARCHAR}
posted @ 2016-12-10 15:58  岁月淡忘了谁  阅读(16702)  评论(0编辑  收藏  举报