C++输出字符指针指向的地址

 1 int main()
 2 {
 3     char *s2 = "jwdajkj";
 4     char *s1 = new char[strlen(s2)+1];
 5     
 6     char *s3 = static_cast<char*> (memcpy(s1, s2, strlen(s2) + 1));
 7     printf("%p,%p\n", s3, s1);
 8     cout << s3 << endl;
 9     cout << &s3[0] << endl;
10     cout << static_cast<void*>(s3) << endl;
11 }

需要转换为void*指针,重载的操作符<<遇到地址会自动输出字符串

posted @ 2017-10-02 01:26  hchacha  阅读(3198)  评论(0编辑  收藏  举报