如何输出e(到20000位)
e就是数学里那个有用的无理数(用来算ln),用数学表达是
#include <iostream> using namespace std; int main(void) { long N, a, b, i, j = 0, k = 0; cin >> N, N += 5; long *e = new long[N], *c = new long[N]; while (++j < N) e[j] = c[j] = 0; for (*c = i = 1; k < N; i++) { while (!c[k]) k++; for (b = 0, j = k - 1; ++j < N; b = a % i) e[j] += (c[j] = (a = b * 10 + c[j]) / i); } for (; --j; e[j] %= 10) e[j - 1] += e[j] / 10; for (cout << "2."; ++j < N - 5;) cout << e[j]; delete[] e, delete[] c; return 0; }