反汇编逆向实例_For语句反汇编

反汇编逆向实例_For语句反汇编

                                                                                                 by:比方

逆向反汇编第二章,For语句反汇编

示例代码:

 1 #include"stdio.h"  
 2 1.int function(int a,int b)  
 3 2.{  
 4 3.    int c=a+b;  
 5 4.    int i;  
 6 5.    for(i=0;i<50;i++)  
 7 6.    {  
 8 7.        c=c+i;  
 9 8.    }  
10 9.    return c;  
11 10.}  
12 11.void main()  
13 12.{  
14 13.    function(1,2);  
15 14.}   

 

反汇编如下

 

1 #include "stdio.h"
2 
3 
4 int function(int a,int b)
5 
6 {

 

011D1A40 push ebp
011D1A41 mov ebp,esp
011D1A43 sub esp,0D8h

 

011D1A49 push ebx                 ;保存环境
011D1A4A push esi       ;保存环境
011D1A4B push edi       ;保存环境
 
011D1A4C lea edi,[ebp-0D8h]
011D1A52 mov ecx,36h
011D1A57 mov eax,0CCCCCCCCh
011D1A5C rep stos dword ptr es:[edi]     ;初始化为0xCC

 

1   int c=a+b;

 

011D1A5E mov eax,dword ptr [a]
011D1A61 add eax,dword ptr [b]
011D1A64 mov dword ptr [c],eax
 
;---------------------------------------------------------------------------------------------
 
1 int i;
2 
3     for(i=0;i<50;i++)
011D1A67 mov dword ptr [i],0                          ;i=0
011D1A6E jmp function+39h (11D1A79h)          ;跳转到判断i是否大于50
 
                                         
011D1A70 mov eax,dword ptr [i]                         ;   
011D1A73 add eax,1                                          ;执行了i=i+1
011D1A76 mov dword ptr [i],eax                         ;   
                                                                         ;     
011D1A79 cmp dword ptr [i],32h                         ;判断i是否大于50
011D1A7D jge function+4Ah (11D1A8Ah)             ;如果大于等于50则跳出for循环,否则继续执行. 

 

1  {               
2 
3         c=c+i;  

 

011D1A7F mov eax,dword ptr [c]                          ;执行了c=c+i;
011D1A82 add eax,dword ptr [i]                           ;    |
011D1A85 mov dword ptr [c],eax                          ;    |

 

011D1A88 jmp function+30h (11D1A70h)              ;如果不大于跳转到执行i++的位置

 

;---------------------------------------------------------------------------------------------、

 

1  return c;

011D1A8A mov eax,dword ptr [c]

 
011D1A8D pop edi   ;恢复环境
011D1A8E pop esi    ;恢复环境
011D1A8F pop ebx   ;恢复环境
 
011D1A90 mov esp,ebp
011D1A92 pop ebp
 
011D1A93 ret

 

posted @ 2014-08-01 15:09  比方  阅读(315)  评论(0编辑  收藏  举报