list文档

文档

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class list(object):     """     list() -> new empty list     list(iterable) -> new list initialized from iterable's items     """     def append(self, p_object): # real signature unknown; restored from __doc__         """          L.append(object) -> None -- append object to end          在列表的最后添加元素         """         pass       def clear(self): # real signature unknown; restored from __doc__         """          L.clear() -> None -- remove all items from L          清楚列表所有元素          """         pass       def copy(self): # real signature unknown; restored from __doc__         """         L.copy() -> list -- a shallow copy of L         复制一个列表         需要注意的是这个拷贝是‘浅拷贝’：         如果列表只有一层（如：l=[1,2,3]）,那么l的copy后列表跟l的内存地址是不同的，但是，         但是，如果l里面嵌套的还有列表（如：l = [1,2,3,[5,6]]）,那么，虽然外层列表地址不同         但是嵌套的[5,6]这个列表（也就是l[3]）的内存地址跟copy后的内存地址不同           ----------------------------------------------------------------------------         l1 = [1,2,[3,4]]         l2 = l1.copy()         print(l1 == l2)         # True         print(l1 is l2)         # False         print(l1[2] is l2[2])   # True           l1[2].append('8')       # 往子列表l[2]里添加元素，l2也会随之改变         print(l2)               # [1, 2, [3, 4, '8']]         ----------------------------------------------------------------------------         如果要深拷贝，则需要导入deepcopy模块         import copy           l1 = [1,2,[3,4]]         l2 = copy.deepcopy(l1)         print(l1 == l2)         # True         print(l2 is l1)         # False           l1[2].append('8')       #往子列表l[2]里添加元素，l2不会随之改变         print(l1)               # [1, 2, [3, 4, '8']]         print(l2)               # [1, 2, [3, 4]]         """         return []       def count(self, value): # real signature unknown; restored from __doc__         """         L.count(value) -> integer -- return number of occurrences of value         计算一个元素在一个列表里出现的次数         """         return 0       def extend(self, iterable): # real signature unknown; restored from __doc__         """         L.extend(iterable) -> None -- extend list by appending elements from the iterable         往列表里拓展元素，参数必须是一个可迭代对象（包括列表，元组以及字符串等……）         """         pass       def index(self, value, start=None, stop=None): # real signature unknown; restored from __doc__         """         L.index(value, [start, [stop]]) -> integer -- return first index of value.         Raises ValueError if the value is not present.         获取列表中某一个元素的索引值，如果有重复元素，只返回第一个         也可以用可选参数start和stop来指定查找范围         """         return 0       def insert(self, index, p_object): # real signature unknown; restored from __doc__         """         L.insert(index, object) -- insert object before index         在指定位置的前一个位置插入指定元素         """           pass       def pop(self, index=None): # real signature unknown; restored from __doc__         """         L.pop([index]) -> item -- remove and return item at index (default last).         Raises IndexError if list is empty or index is out of range.         删除列表的元素，可以按索引来指定删除的元素，不指定的话默认删除最后一个         如果指定索引超出范围，则会报错         """         pass       def remove(self, value): # real signature unknown; restored from __doc__         """         L.remove(value) -> None -- remove first occurrence of value.         Raises ValueError if the value is not present.         按照元素值来删除列表的元素         如果指定元素不存在则会报错         """         pass       def reverse(self): # real signature unknown; restored from __doc__         """         L.reverse() -- reverse *IN PLACE*         将一个列表反转         """         pass       def sort(self, key=None, reverse=False): # real signature unknown; restored from __doc__         """         L.sort(key=None, reverse=False) -> None -- stable sort *IN PLACE*         将列表按照指定的规则排序         可以用key来指定排序规则，不指定的话默认按照asc码来排序         字符串不能跟数字类型一起排序         ----------------------------------------------------------------------         l1 = [1,2,5,3,8,6]         l1.sort()         print(l1)               # [1, 2, 3, 5, 6, 8]           l2 = ['c','b','a']      # ['a', 'b', 'c']         l2.sort()         print(l2)           l3 = ['fuyong','age','name']         l3.sort()         print(l3)               # ['age', 'fuyong', 'name']         ----------------------------------------------------------------------         key是一个可选的参数，接收一个函数名或者一个匿名函数         l4 = [(1,3),(2,1),(3,2)]         l4.sort(key=lambda x:x[0])         print(l4)                   # [(1, 3), (2, 1), (3, 2)]         l4.sort(key=lambda x:x[1])         print(l4)                   # [(2, 1), (3, 2), (1, 3)]         ----------------------------------------------------------------------         l5 = [{'age':13},{'age':18},{'age':16}]         l5.sort(key=lambda x:x['age'])         print(l5)               # [{'age': 13}, {'age': 16}, {'age': 18}]         ----------------------------------------------------------------------         可以用reverse参数来指定是正序还是倒叙，不指定的话默认正序         l5.sort(key=lambda x:x['age'],reverse=True         print(l5)               # [{'age': 18}, {'age': 16}, {'age': 13}]         """         pass

　　

示例

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l1 = [1,2,[3,4]] l2 = l1.copy()   print(l1 == l2) print(l1 is l2) print(l1[2] is l2[2])   l1[2].append('8') print(l2)   import copy   l1 = [1,2,[3,4]] l2 = copy.deepcopy(l1) print(l1 == l2) print(l2 is l1)   l1[2].append('8') print(l1) print(l2)   l = [1,2,3,4,5,6] l.pop() print(l) l.pop(3) print(l)   l1 = [1,2,5,3,8,6] l1.sort() print(l1)   l2 = ['c','b','a'] l2.sort() print(l2)     l3 = ['fuyong','age','name'] l3.sort() print(l3)   l4 = [(1,3),(2,1),(3,2)] l4.sort(key=lambda x:x[0]) print(l4) l4.sort(key=lambda x:x[1]) print(l4)   l5 = [{'age':13},{'age':18},{'age':16}] l5.sort(key=lambda x:x['age']) print(l5) l5.sort(key=lambda x:x['age'],reverse=True) print(l5)