正则表达式中\d和[0-0]有什么区别
今天看到Stackoverflow上一个有趣的问题,为什么正则表达式在中\d比[0-0]低效?
提问者用了如下的代码来做测试:
static void Main(string[] args) { var rand = new Random(1234); var strings = new List<string>(); //10K random strings for (var i = 0; i < 10000; i++) { //Generate random string var sb = new StringBuilder(); for (var c = 0; c < 1000; c++) { //Add a-z randomly sb.Append((char)('a' + rand.Next(26))); } //In roughly 50% of them, put a digit if (rand.Next(2) == 0) { //Replace one character with a digit, 0-9 sb[rand.Next(sb.Length)] = (char)('0' + rand.Next(10)); } strings.Add(sb.ToString()); } var baseTime = testPerfomance(strings, @"\d"); Console.WriteLine(); var testTime = testPerfomance(strings, "[0-9]"); Console.WriteLine(" {0:P2} of first", testTime.TotalMilliseconds / baseTime.TotalMilliseconds); testTime = testPerfomance(strings, "[0123456789]"); Console.WriteLine(" {0:P2} of first", testTime.TotalMilliseconds / baseTime.TotalMilliseconds); } private static TimeSpan testPerfomance(List<string> strings, string regex) { var sw = new Stopwatch(); int successes = 0; var rex = new Regex(regex); sw.Start(); foreach (var str in strings) { if (rex.Match(str).Success) { successes++; } } sw.Stop(); Console.Write("Regex {0,-12} took {1} result: {2}/{3}", regex, sw.Elapsed, successes, strings.Count); return sw.Elapsed; } }
得到的输出结果是:
Regular expression \d took 00:00:00.2141226 result: 5077/10000 Regular expression [0-9] took 00:00:00.1357972 result: 5077/10000 63.42 % of first Regular expression [0123456789] took 00:00:00.1388997 result: 5077/10000 64.87 % of first
从这个测试中可以看出\d比[0-9]慢了一倍。
原因在于,\d会比较所有的unicode的数字,包括
0123456789٠١٢٣٤٥٦٧٨٩۰۱۲۳۴۵۶۷۸۹߀߁߂߃߄߅߆߇߈߉०१२३४५६७८९০১২৩৪৫৬৭৮৯੦੧੨੩੪੫੬੭੮੯૦૧૨૩૪૫૬૭૮૯୦୧୨୩୪୫୬୭୮୯௦௧௨௩௪௫௬௭௮௯౦౧౨౩౪౫౬౭౮౯೦೧೨೩೪೫೬೭೮೯൦൧൨൩൪൫൬൭൮൯๐๑๒๓๔๕๖๗๘๙໐໑໒໓໔໕໖໗໘໙༠༡༢༣༤༥༦༧༨༩၀၁၂၃၄၅၆၇၈၉႐႑႒႓႔႕႖႗႘႙០១២៣៤៥៦៧៨៩᠐᠑᠒᠓᠔᠕᠖᠗᠘᠙᥆᥇᥈᥉᥊᥋᥌᥍᥎᥏᧐᧑᧒᧓᧔᧕᧖᧗᧘᧙᭐᭑᭒᭓᭔᭕᭖᭗᭘᭙᮰᮱᮲᮳᮴᮵᮶᮷᮸᮹᱀᱁᱂᱃᱄᱅᱆᱇᱈᱉᱐᱑᱒᱓᱔᱕᱖᱗᱘᱙꘠꘡꘢꘣꘤꘥꘦꘧꘨꘩꣐꣑꣒꣓꣔꣕꣖꣗꣘꣙꤀꤁꤂꤃꤄꤅꤆꤇꤈꤉꩐꩑꩒꩓꩔꩕꩖꩗꩘꩙0123456789
可以从这里看到更全的列表,列出了所有Unicode中属于数字的字符。
如果在生成Regex的时候传入一个参数RegexOptions.ECMAScript
,如下所示,那么\d就和[0-9]的效率一样了。可以从这里找到更多的Regex的选项。
var rex = new Regex(regex, RegexOptions.ECMAScript);