输入一个正整数repeat(0<repeat<10),做repeat次下列运算:读入1个实数x和1个正整数n(n<=50),计算并输出x的n次幂。
代码:
1 import java.util.*;
2 public class Main {
3 public static void main (String [] args) {
4 int repeat,n;
5 double x;
6 Scanner s=new Scanner(System.in);
7 repeat=s.nextInt();
8 for(int i=1;i<=repeat;i++) {
9 x=s.nextDouble();
10 n=s.nextInt();
11 double pow=Math.pow(x,n);
12 System.out.println(String.format("%.2f", pow));
13 }
14 }
15 }