单向链表的归并排序——java实现

在做Coursera上的Algorithms第三周测验练习的时候有一道链表随机排序问题，刚开始没有什么思路，就想着先把单向链表归并排序实现了，再此基础上进行随机排序的改造。于是就结合归并排序算法，实现了单向链表的归并排序。

  1 import java.util.Iterator;
  2 /**
  3  * 对单向链表的由小到大归并排序
  4  * @author evasean www.cnblogs.com/evasean/
  5  * @param <T>
  6  */
  7 public class MergeSortLinkedList <T extends Comparable<T>> implements Iterable<T>{
  8     private Node first = null;
  9     private Node last = null;
 10     private int n;
 11     private class Node{
 12         T element;
 13         Node next;
 14     }
 15     private boolean less(Comparable v, Comparable w) {
 16         return v.compareTo(w) < 0;
 17     }
 18     @Override
 19     public Iterator<T> iterator() {
 20         // TODO Auto-generated method stub
 21         return new ListIterator();
 22     }
 23     private class ListIterator implements Iterator<T>{
 24         private Node current = first;
 25         @Override
 26         public boolean hasNext() {
 27             // TODO Auto-generated method stub
 28             return current != null;
 29         }
 30 
 31         @Override
 32         public T next() {
 33             // TODO Auto-generated method stub
 34             T t = current.element;
 35             current = current.next;
 36             return t;
 37         }
 38     }
 39     public void add(T t){
 40         Node node = new Node();
 41         node.element = t;
 42         node.next = null;
 43         if(first == null && last == null){
 44             first = node;
 45             last = node;
 46         }else if(first != null && first == last){
 47             first.next = node;
 48             last = node;
 49         }else{
 50             last.next = node;
 51             last = node;
 52         }
 53         n++;
 54     }
 55     @Override
 56     public String toString(){
 57         Iterator<T> iter = iterator();
 58         String ret = iter.next().toString();
 59         while(iter.hasNext()){
 60             ret += ", "+ iter.next().toString() ;
 61         }
 62         return ret;    
 63     }
 64     public void mergeSort(){
 65         first = sort(first);
 66     }
 67     
 68     private Node sort(Node head){
 69         if(head == null || head.next == null) return head;
 70         Node slow = head;
 71         Node fast = head;
 72         //取中间节点
 73         while(fast.next != null && fast.next.next != null){
 74             slow = slow.next;
 75             fast = fast.next.next;
 76         }
 77         Node left = head;
 78         Node right = slow.next;
 79         slow.next = null; //将左右链表分开
 80         left = sort(left);
 81         right = sort(right);
 82         return merge(left,right);
 83     }
 84     private Node merge(Node left, Node right){
 85         //System.out.println("left="+left.element+",right="+right.element);
 86         Node aux = new Node(); //需要耗费logn的额外空间
 87         Node l= left;
 88         Node r = right;
 89         Node current = aux;
 90         while(l != null && r!=null){
 91             if(less(r.element,l.element)) {
 92                 current.next = r;
 93                 current = current.next;
 94                 r = r.next;
 95             }
 96             else {
 97                 current.next = l;
 98                 current = current.next;
 99                 l= l.next;
100             }
101         }
102         if(l!=null) current.next = l; // 如果左侧没遍历完，将其连接至current后
103         else if(r != null) current.next = r; //如果右侧没遍历完，将其连接至current后
104         return aux.next; //返回归并好的链表
105     }
106      public static void main(String[] args){
107          ShuffleLinkedList<Integer> sll = new ShuffleLinkedList<Integer>();
108          sll.add(1);
109          sll.add(2);
110          sll.add(11);
111          sll.add(9);
112          sll.add(10);
113          sll.add(4);
114          sll.add(7);
115          System.out.println(sll);
116          sll.mergeSort();
117          System.out.println(sll);
118      }
119 
120 }

 

posted @ 2017-07-25 10:25  evasean  阅读(1608)  评论(0)  编辑  收藏  举报