【leetcode】Spiral Matrix(middle)

Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.

For example,
Given the following matrix:

[
 [ 1, 2, 3 ],
 [ 4, 5, 6 ],
 [ 7, 8, 9 ]
]

You should return [1,2,3,6,9,8,7,4,5].

 

思路:就按照螺旋矩阵的规律 用n记录旋转圈数 每圈按左下右上的顺序取值。 注意去重复。

class Solution {
public:
    vector<int> spiralOrder(vector<vector<int> > &matrix) {
        vector<int> ans;
        if(matrix.empty())
            return ans;
        int M = matrix.size();
        int N = matrix[0].size();

        for(int n = 0; n < min((M+1)/2,(N+1)/2);n++)
        {
            //行 ----->
            for(int i = n; i < N - n; i++)
                ans.push_back(matrix[n][i]);
            //列 向下
            for(int i = n + 1; i < M - n; i++)
                ans.push_back(matrix[i][N - 1 - n]);
            //行 <-----------
            if(M - n - 1 <= n) //列号 一定要比向左时的列号小 防止重复
                break;
            for(int i = N - n - 2; i >= n; i--)
                ans.push_back(matrix[M - n - 1][i]);
            //列 向上
            if(n >= N - 1 - n) //行号 一定要比向下时的行号大 防止重复
                break;
            for(int i = M - n - 2; i >= n + 1; i--)
                ans.push_back(matrix[i][n]);
        }
        return ans;    
    }
};

 

大神思路和我一样,就是用自定义变量来避免重复取行或列。

public class Solution {
    public List<Integer> spiralOrder(int[][] matrix) {
        List<Integer> res = new ArrayList<Integer>();
        if (matrix.length == 0) {
            return res;
        }
        int rowBegin = 0;
        int rowEnd = matrix.length-1;
        int colBegin = 0;
        int colEnd = matrix[0].length - 1;

        while (rowBegin <= rowEnd && colBegin <= colEnd) {
            // Traverse Right
            for (int j = colBegin; j <= colEnd; j ++) {
                res.add(matrix[rowBegin][j]);
            }
            rowBegin++;

            // Traverse Down
            for (int j = rowBegin; j <= rowEnd; j ++) {
                res.add(matrix[j][colEnd]);
            }
            colEnd--;

            if (rowBegin <= rowEnd) {
                // Traverse Left
                for (int j = colEnd; j >= colBegin; j --) {
                    res.add(matrix[rowEnd][j]);
                }
            }
            rowEnd--;

            if (colBegin <= colEnd) {
                // Traver Up
                for (int j = rowEnd; j >= rowBegin; j --) {
                    res.add(matrix[j][colBegin]);
                }
            }
            colBegin ++;
        }

        return res;
    }
}

 

posted @ 2015-03-17 21:57  匡子语  阅读(186)  评论(0编辑  收藏  举报