PAT甲题题解-1025. PAT Ranking (25)-排序
排序,求整体的排名和局部的排名
整体排序,for循环一遍
同时存储整体目前的排名和所在局部的排名即可
#include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> #include <queue> #include <map> using namespace std; const int maxn=105; const int maxk=305; int local_Rank[maxn]; //local_Rank[i]表示第i个组目前的排名 int last_local_id[maxn]; //last_local_id[i]表示第i个组前一个在整体中的索引 struct Node{ long long id; int score; int group; int ranks; int local_rank; bool operator<(const Node tmp)const{ if(score==tmp.score) return id<tmp.id; else return score>tmp.score; } }stu[maxn*maxk]; int main() { int n,k; scanf("%d",&n); int cnt=0; long long id; int score; for(int i=1;i<=n;i++){ scanf("%d",&k); for(int j=0;j<k;j++){ scanf("%lld %d",&id,&score); stu[cnt].id=id; stu[cnt].score=score; stu[cnt].group=i; cnt++; } } printf("%d\n",cnt); sort(stu,stu+cnt); memset(local_Rank,0,sizeof(local_Rank)); int global_rank=0; //整体排名 for(int i=0;i<cnt;i++){ if(global_rank==0){ stu[i].ranks=1; global_rank=1; } else{ if(stu[i].score==stu[i-1].score){ stu[i].ranks=stu[i-1].ranks; global_rank++; } else{ global_rank++; stu[i].ranks=global_rank; } } int group=stu[i].group; if(local_Rank[group]==0){ stu[i].local_rank=1; local_Rank[group]=1; last_local_id[group]=i; } else{ int id=last_local_id[group]; if(stu[i].score==stu[id].score){ stu[i].local_rank=stu[id].local_rank; local_Rank[group]++; } else{ local_Rank[group]++; stu[i].local_rank=local_Rank[group]; last_local_id[group]=i; } } printf("%013lld %d %d %d\n",stu[i].id,stu[i].ranks,stu[i].group,stu[i].local_rank); } return 0; }