链表反转

链表反转简单实现

Node* rever(Node* Head)
{   
    if(Head == NULL || Head->next == NULL)
        return Head;
    Node* cur, next, next_next;
    cur = Head; 
    next = cur->next;
    while(cur->next != NULL){
        next_next = next->next;
        next->next = cur;
        cur = next;
        next = next_next;
    }
    Head->next = NULL;
    return cur;
}

  

posted @ 2016-09-20 10:56  tcgoshawk  阅读(94)  评论(0编辑  收藏  举报