835.Hamming距离

描述

两个整数的Hamming距离是对应比特位不同的个数。
给定两个整数x和y，计算两者的Hamming距离。

0 ≤ x, y < 2^31.

您在真实的面试中是否遇到过这个题？

样例

输入: x = 1, y = 4

输出: 2

public class Solution {
    /**
     * @param x: an integer
     * @param y: an integer
     * @return: return an integer, denote the Hamming Distance between two integers
     */
    public int hammingDistance(int x, int y) {
        int diff = x ^ y;
        return Integer.bitCount(diff);
    }
}

public class Solution {
    /**
     * @param x: an integer
     * @param y: an integer
     * @return: return an integer, denote the Hamming Distance between two integers
     */
    public int hammingDistance(int x, int y) {
        // write your code here
        
        int res = 0;
        while(x!=0 || y!=0){
            int remX = x % 2;
            int remY = y % 2;
            if((remX ^ remY) == 1){
                res++;
            }
            x = x >> 1;
            y = y >> 1;
        }
        return res;
        
    }
}