LCA(st算法)

#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<iostream>
#include<cmath>
#define maxn 500000
using namespace std;
int dp[1001000][20];
int to[maxn*2],be[maxn*2],ne[2*maxn],e;
int deep[maxn*2],first[2*maxn],cnt,n;
bool p[maxn];
void add(int x,int y){
	to[++e]=y;
	ne[e]=be[x];
	be[x]=e;
}
void dfs(int v,int deepth){
	p[v]=1,dp[++cnt][0]=v,first[v]=cnt;
	for(int i=be[v];i;i=ne[i]){
		if(!p[to[i]]){
			deep[to[i]]=deepth;
			dfs(to[i],deepth+1);
			dp[++cnt][0]=v;
		}
	}
}
void st(int n){
	int len=log2(n)+1;
	for(int i=1;i<=len;i++){
		for(int j=1;j<=n;j++){
			if(j+(1<<(i-1))>n)continue;
			if(deep[dp[j][i-1]]<deep[dp[j+(1<<(i-1))][i-1]])
			dp[j][i]=dp[j][i-1];
			else dp[j][i]=dp[j+(1<<(i-1))][i-1];
		}
	}
}
int rmq(int a,int b){
	if(a>b)swap(a,b);
	int k1=log2(b-a+1);
	int x,y;
	x=dp[a][k1];
	y=dp[b-(1<<k1)+1][k1];
	if(deep[x]>deep[y])return y;
	else return x;
}
int main(){
	int i,j,k,m;
	scanf("%d%d%d",&n,&m,&k);
	for(i=1;i<=n-1;i++){
		int x,y;
		scanf("%d%d",&x,&y);
		add(x,y);
		add(y,x);
	}
	dfs(k,1);
	st(cnt);
	for(i=1;i<=m;i++){
		int x,y;
		scanf("%d%d",&x,&y);
		printf("%d\n",rmq(first[x],first[y]));
	}	
	return 0;
}

posted @ 2016-12-24 17:14  Drinkwater_cnyali  阅读(120)  评论(0编辑  收藏  举报